- Manuka Honey MGO 550+ is 100% natural and rich in methylglyoxal honey with anti-inflammatory and antibacterial. Manuka honey is particularly suitable for children and adults with reduced immune resistance. ORIGINAL PRODUCT.
100% honey bush Manuka
Honey contains the active ingredient methylglyoxal in quantities greater than 550 mg / kg (a natural constituent present in significant amounts only in some Manuka honey).
Nutritional value 5 g *
The energy value of 70 kJ / 16.7 kcal
Fat 0 g
of saturated fatty acids 0 g
Carbohydrates 4.1 g
of which sugars 4.1 g
Protein Negligible amounts of
salt 2.5 g
Methylglyoxal> 2 mg
* 5 grams (a teaspoon) = 1 serving. The jar is 50 servings. Action: Manuka Honey MGO 550+ is the highest quality, all natural, original and certified product coming from New Zealand, considered the healthiest of honey on the market. 550+ Manuka honey is characterized by the highest dose of methylglyoxal - 550 mg / kg (MGO ™ 550+) here shows a really significant impact on the immune resistance in both children and adults. Manuka Honey is a food product, also indicated for people suffering from ailments of the digestive system and is sometimes recommended as a product to accelerate the healing of wounds and skin ulcers - a strong antibacterial and antifungal honey.The properties of Manuka Honey has been proven in many scientific reports, and the method MGO - the test method properties and potency of Manuka is considered the most reliable method for measuring the properties of this type of honey.
Consuming manuka honey MGO® 550+:
Honey is best consumed in the morning on an empty stomach in the amount of 2-3 teaspoons or 1 teaspoon 2-3 times a day half an hour before a meal. Honey is ideally suited as an additive to foods and beverages.